Suggestion:Use the String direct value for the assignment

Do u knw the String Object ? If u do some projects,u can see the
String is used usually. A object is created by the key word :
new.Therefore , we can create a String Obejct by :“ 

String str3 = new String("Jeff"); ” .

Here, in my word,using the String direct value for the assignment is a better way.

for example:

public class String01
{
    public static void main(String[] args)
    {
        String str1 = "Jeff";
        String str2 = "Jeff";
        String str3 = new String("Jeff");
        String str4 = str3.intern();

        boolean b1 = (str1 == str2);
        boolean b2 = (str1 == str3);
        boolean b3 = (str1 == str4);

        System.out.println("b1:"+b1+"  "+"b2:"+b2+"  "+"b3:"+b3+"  ");
    }
}
#outputs:
b1:true  b2:false  b3:true

b1:true b2:false
u will think ,thats why they r different.
As we all kno , the  operator“==”show whether two objects’address references
are the same. Java designed a String Pool for storing all the String
used to avoid there are to many String Objects created in a system. So 
String str3 = new String("Jeff");  is creating a object in java heap memory not the String Pool.

intern() is a method of String. we can see from the jdk help doc.

public String intern()
Returns a canonical representation for the string object.
A pool of strings, initially empty, is maintained privately by the class String.

When the intern method is invoked, if the pool already contains a string equal to this String object as determined by the equals(Object) method, then the string from the pool is returned. Otherwise, this String object is added to the pool and a reference to this String object is returned.

It follows that for any two strings s and t, s.intern() == t.intern() is true if and only if s.equals(t) is true.

All in all, using  String str = "Jeff";  u dont mind the Thread-security or Garbage collection mechanism.String is a nice man , treat it as a little boy pelasse.

How to use the String , StringBuffer,StringBuilder

Look at the pic:
                              

String , StringBuffer ,StringBuilder implement the CharSequence.But they are different.

String
String Object is a non-variable . it can not be changed and in the memory when u create it.

for example:

String str  = "abc";
    String str1 = str.substring(1);

    System.out.println("str1" + str1);

#outputs:
bc

substring() method creates a new String Object and links the
reference of it to str1. But when “str.substring(0)”,str1 and str  both
link to the “abc”by the JVM.

StringBuffer StringBuilder

they are very similar and they r variables of the sequence of
characters.Only different, the StringBuffer has the methods which are
synchronized where necessary. String buffers are safe for use by
multiple threads. Different from String, if z refers to a string buffer object whose current contents are "start", then the method call z.append("le") would cause the string buffer to contain "startle", whereasz.insert(4, "le") would alter the string buffer to contain "starlet".

All in all:

String can be used for the constants.

StringBuffer can be used for some operating methods in multithreaded environment.like XML analyze,the parameters of HTTP analyze etc.

StringBuilder can be used for HQL/SQL splice, JSON package etc.

Easy Time:Pay attention to the address of String

for example:

public static void main(String[] args)
{
    String str1 = 1 + 2 + "apples";
    String str2 = "apples" + 1 + 2;

    System.out.println(str1);
    System.out.println(str2);
}
#outputs:
3apples
apples12

what we can see from the result-values.why ? how ? they did.

Because the JAVA handling mechanism to the operator “+”. when there
is a string in the expression, all the expression data will change
itself to the String class.if the data is an Object, it will call its
toString method.

So,String str1 = 1 + 2 + "apples" just like String str1 = (1 + 2) + "apples" .thats all.

Complex string manipulation using regular expressions

just reading！！ the part ， i will write in the future.