问题描述
- 求大神解决VC++等值线插值程序无输出问题
-
本人C++水平一般，编了一个小程序，调试已过，具体算法就是输进一组由两条等值线数值及坐标构成的数组，然后取三个点找外接圆圆心，再从圆心0-180度内每隔45度引射线与原等值线想交，再找出交点的中点并输出。。。目前测试过数组能正常读入。。。但是输出无结果，求指教，主程序如下
#include
#include
#include
#include
#define shuliang 10000
#define gaodu 1024
#define kuandu 1024
using namespace std;
static int yuanxinx = 0;
static int yuanxiny = 0;
static int jiaodianax = 0;
static int jiaodianay = 0;
static int jiaodianbx = 0;
static int jiaodianby = 0;
static int count1 = 0;
const double pi = 3.1415927;
int juli(int a, int b,int c , int d)//输入两个点的坐标，计算两点间距离
{return sqrt(pow((a - c), 2) + pow((b - d), 2));
}
bool yuanxin(int ax, int ay, int bx, int by, int cx, int cy)//输入三个点坐标，计算圆心
{
int a, b, c;
bool i=1;
for (int x = 0; x <= gaodu; x++)
{
for (int y = 0; y <= kuandu; y++)
{
a = pow((x - ax), 2) + pow((y - ay), 2);
b = pow((x - bx), 2) + pow((y - by), 2);
c = pow((x - cx), 2) + pow((y - cy), 2);
if (fabs(a-b)<exp(-5)&&fabs(c-b)<exp(-5))
{
yuanxinx = x;
yuanxiny = y;
return i;
break;
}
else i = 0;
return i;
}
}}
bool zhaojiaodian(int ax, int ay, int a[shuliang][3],int qiyaa,int qiyab)//输入圆心和所有点，寻找所需焦点
{int d, e, f;
double g1;
double g2;
double h1;
double h2;
int angle;
bool p=1;for (int n = 0; n <= shuliang; n++)
{for(int dx = 0;dx<=kuandu;dx++)
{for(int ex = 0;ex <= kuandu;ex++)
{
for (int dy = 0;dy <= gaodu; dy++)
{for(int ey =0 ;ey <= gaodu; ey++)
{
if ((a[n][1] == ex && a[n][2] == ey)||(a[n][1] == dx && a[n][2] == dy))
{d = sqrt(pow(ax-dx,2) + pow(ay-dy,2));
e = sqrt(pow(ax-ex,2) + pow(ay-ey,2));
f = sqrt(pow(dx-ex,2) + pow(dy-ey,2));
if (fabs(e-f-d)<exp(-5))
{
for(int i = 0 ;i <= 4 ; i++)
{
g1 = (ay-dy)/(ax-dx);
g2 = 0;
h1 = atan(g1);
h2 = atan(g2);
angle = fabs(h1 - h2);
if (fabs(angle- i*pi/4)<exp(-5))
{
jiaodianax = dx;
jiaodianay = dy;
jiaodianbx = ex;
jiaodianby = ey;
return p;
break;
}
else p = 0;
return p;
}
}
}
}
}
}
}
}
}
int zhongzhidianx(int ax, int bx)
{
return ax + (bx - ax) / 2;
}
int zhongzhidiany(int ay,int by)
{
return ay + (by - ay) / 2;
}
void main()
{
int a[shuliang][3]; //建立二维数组ifstream infile("input.txt", ios::in); //打开已存在的输入文件input.txt if (!infile) { cout << "输入文件input.txt不存在n"; exit(0); } ofstream outfile; //创建输出文件，若存在则清除该文件内容 outfile.open("output.txt", ios::out); if (!outfile) { cout << "不能建立输出文件output.txtn"; exit(0); } char str[2000][20]; int i = 0; while (!infile.eof()) { infile.getline(str[i], 20); i++; } count1 = i; int flag = 0; int value = 0; for (int k = 0; k <= count1; k++) { flag = 0; value = 0; for (int l = 0; str[k][l] != ''; l++) { if (str[k][l] != 't') { value = value * 10 + (str[k][l] - '0'); } if (str[k][l] == 't' || str[k][l + 1] == '') { a[k][flag] = value; value = 0; flag++; } } }} } infile.close(); outfile.close();}
解决方案
http://download.csdn.net/download/bllb007/3634119
解决方案二：
头文件复制上来就不见了。。。。
解决方案三：
如果你算法数据已经正确，那么输出文件，就是可以把结果组成i一个字符串，然后out一次性写入文件。