问题描述

python 新手 提问，求教，多谢！

#-*_coding:utf8-*-
import requests
import re
import sys
from lxml import etree

reload(sys)
sys.setdefaultencoding(""utf-8"")

url = 'https://movie.douban.com/people/li2007/collect?start=0&sort=time&rating=all&tag=.%E7%94%B5%E5%BD%B1&mode=grid&filter=all'

j = 0
all_links = []
for i in range(2):
link = re.sub('start=d' 'start=%d' % j url re.S)
all_links.append(link)
j += 15

all_htmls = []
for i in range(2):
html = requests.get(all_links[i]).text
all_htmls.append(html)

all_items = []
for i in range(2):
selector = etree.HTML(all_htmls[i])
item_group = selector.xpath('//div[@class=""grid-view""]/div[@class=""item""]/div[@class=""info""]/ul/li[@class=""title""]/a/@href')
for j in range(len(item_group)):
all_items.append(item_group[j])

all_infos = []
for i in range(len(all_items)):
info = {}
titlelink = all_items[i]
titlehtml = requests.get(titlelink).text
selector = etree.HTML(titlehtml)
info['title'] = selector.xpath('//span[@property=""v:itemreviewed""]/text()')
info['date'] = selector.xpath('//span[@class=""year""]/text()')
info['rating'] = selector.xpath('//strong[@class=""ll rating_num""]/text()')
all_infos.append(info)

f = open('info.txt' 'a')
j = 1
for each in all_infos:
f.writelines('No.:' + str(j) + 'n')
f.writelines('Title:' + each['title'] + 'n')
f.writelines('Date:' + each['date'] + 'n')
f.writelines('Rating:' + each['rating'] + 'nn')
j += 1
f.close()
print j

这段代码运行后会报错，错误在

f.writelines('Title:' + each['title'] + 'n')
f.writelines('Date:' + each['date'] + 'n')
f.writelines('Rating:' + each['rating'] + 'nn')
这几行，提示：
Traceback (most recent call last):
File ""D:/D/PycharmProjects/untitled/456.py"" line 46 in
f.writelines('Title:' + each['title'] + 'n')
TypeError: cannot concatenate 'str' and 'list' objects
百思不得其解，新手，正在试着自学入门python，请留情，请指教，多谢多谢！

另外：
我如果改成
str( each['title'])
str( each['date'])
str( each['rating'])
的话，程序可以运行，但是结果会是这样子：

No.:1
Title:[u'u5144u5f1f Brxf8dre']
Date:['(2015)']
Rating:['8.9']

No.:2
Title:[u'u6c42u804cu8bb0 Get a Job']
Date:['(2016)']
Rating:[]

No.:3
Title:[u'u5931u5e38 Anomalisa']
Date:['(2015)']
Rating:['7.4']

No.:4
Title:[u'u8759u8760u4fa0u5927u6218u8d85u4ebauff1au6b63u4e49u9eceu660e Batman v Superman: Dawn of Justice']
Date:['(2016)']
Rating:['6.7']

No.:5
Title:[u'u7231u60c5u91cdu51fb Love Punch']
Date:['(2013)']
Rating:['6.4']

No.:6
Title:[u'u98deu8dc3u60c5u6d77 Beyond the Sea']
Date:['(2004)']
Rating:['7.6']

No.:7
Title:[u""u8ff7u59311971 '71""]
Date:['(2014)']
Rating:['7.1']

No.:8
Title:[u'u6b7bu4f8d Deadpool']
Date:['(2016)']
Rating:['7.6']

No.:9
Title:[u'u7b2cu4e94u6ce2 The 5th Wave']
Date:['(2016)']
等等....

可我想要的结果是
No.:1
Title:Br?dre
Date:(2015)
Rating:8.9

为什么呢？

解决方案

第一个title那个应该是编码的问题，转换一下就好，另外的两个因为是列表所以加上下标就好了，我也是个新手，欢迎讨论

解决方案二：
title的编码，你需要decode成对应语言的编码格式