问题描述
接口变量如何序列化？现有一个内部接口如下 public interface GetDataInterface<K> extends Serializable { public Object getData(K key); }new接口的变量并序列化如下GetDataInterface<String> getData = new GetDataInterface<String>() {private static final long serialVersionUID = 1L;@Overridepublic Object getData(String key) {return null;}};ObjectOutputStream out = new ObjectOutputStream(new FileOutputStream("a.obj"));out.writeObject(getData);out.close();始终报ioexception如下IOException java.io.NotSerializableException: [java.io.ObjectOutputStream.writeObject0(Unknown Source), java.io.ObjectOutputStream.defaultWriteFields(Unknown Source), java.io.ObjectOutputStream.writeSerialData(Unknown Source), java.io.ObjectOutputStream.writeOrdinaryObject(Unknown Source), java.io.ObjectOutputStream.writeObject0(Unknown Source), java.io.ObjectOutputStream.writeObject(Unknown Source)]如果建一个类继承自GetDataInterface再实例化该类的变量进行序列化不会出现问题，问下是不是像上面的接口变量无法进行序列化，有没有办法进行序列化（不新建类继承接口）
解决方案
亲，完全没有问题啊。不知道你咋不行呢？public class Tests{ interface A<K> extends Serializable { public Object getData(K key); } public static void main(String[] args){A<String> getData = new A<String>() { private static final long serialVersionUID = 1L; @Override public Object getData(String key) { return null; } }; ObjectOutputStream out;try {out = new ObjectOutputStream(new FileOutputStream("a.obj"));out.writeObject(getData); out.close();} catch (FileNotFoundException e) {// TODO Auto-generated catch blocke.printStackTrace();} catch (IOException e) {// TODO Auto-generated catch blocke.printStackTrace();} }}
解决方案二：
内容： sr com.javac.demo.Tests$1 xp