问题描述
publicstaticvoidmain(String[]args){Stringstr="{"name":"Michael","address":{"city":"Beijing","street":"ChaoyangRoad","postcode":100025}}";StringstrTwo="{"address":{"city":"Beijing","street":"ChaoyangRoad","postcode":100025},"name":"Michael"}";System.out.println(compareJson(str,strTwo));}str和StrTwo应该是相同的compareJson(str1,str2);方法如何写？
解决方案
解决方案二：
转成对象，然后比较里面的字段值
解决方案三：
转成队形再比较
解决方案四：
对象取出来放数组里，再进行对比
解决方案五：
的字段值
解决方案六：
试试structx{publicstringname;publicyaddress;}structy{publicstringcity;publicstringstreet;publicintpostcode;}
stringstr="{"name":"Michael","address":{"city":"Beijing","street":"ChaoyangRoad","postcode":100025}}";stringstrTwo="{"address":{"city":"Beijing","street":"ChaoyangRoad","postcode":100025},"name":"Michael"}";Console.WriteLine(fastCSharp.emit.equals<x>.Equals(fastCSharp.emit.jsonParser.Parse<x>(str),fastCSharp.emit.jsonParser.Parse<x>(strTwo)));
解决方案七：
解决方案八：
usingNewtonsoft.Json;usingNewtonsoft.Json.Converters;publicclassfarm{publicintid{get;set;}publicstringutime{get;set;}publicstringplayername{get;set;}publicstringfarmname{get;set;}publicintzlevel{get;set;}publicintblood{get;set;}publicintx{get;set;}publicinty{get;set;}publicintrice{get;set;}publicintstat{get;set;}publicintspeed{get;set;}publicintstep{get;set;}publicstringpic{get;set;}publicintmaxstorage{get;set;}publicintworkstep{get;set;}publicintriceoutput{get;set;}publicstringzmessage{get;set;}}List<farm>tmplist=JsonConvert.DeserializeObject<List<farm>>(s);
解决方案九：
1、将json转成datatable2、比较datatable